A simple spring has length l and force constant k. It is cut into two springs of lengths l1 and l2 such that l1=nl2(n=integer). The force constant of the spring of length l1 is
A
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B
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C
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D
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Solution
The correct option is B Let k1 be the spring constant of spring of length l1 and k2 be the spring constant of spring length l2. Since l1=nl2, the spring is made of (n+1) equal parts in lengths each of length l2. ∴1k=(n+1)k2∴k2=k(n+1) The spring of length l1 is equivalent to n springs in series. ∴k1=kn=(n+1n)k