wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A simple spring has length l and force constant k. It is cut into two springs of lengths l1 and l2 such that l1=nl2(n=integer). The force constant of the spring of length l1 is

A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B
Let k1 be the spring constant of spring of length l1 and k2 be the spring constant of spring length l2. Since l1=nl2, the spring is made of (n+1) equal parts in lengths each of length l2.
1k=(n+1)k2 k2=k(n+1)
The spring of length l1 is equivalent to n springs in series.
k1=kn=(n+1n)k

flag
Suggest Corrections
thumbs-up
17
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Energy in SHM
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon