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Byju's Answer
Standard XII
Physics
Wave Equation
A simple wave...
Question
A simple wave motion represented by
y
=
5
(
sin
4
π
t
+
√
3
cos
4
π
t
)
. Its amplitude is:
A
5
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B
5
√
3
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C
10
√
3
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D
10
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Solution
The correct option is
C
10
y
=
5
(
s
i
n
4
π
t
+
√
3
c
o
s
4
π
t
)
=
5
×
2
(
1
2
s
i
n
4
π
t
+
√
3
2
c
o
s
4
π
t
)
=
10
(
c
o
s
π
3
s
i
n
4
π
t
+
s
i
n
π
3
c
o
s
4
π
t
)
=
10
s
i
n
(
4
π
t
+
π
3
)
Hence the amplitude of the wave is
10
.
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0
Similar questions
Q.
Two simple harmonic motions are represented by
y
1
=
4
sin
(
4
π
t
−
π
2
)
and
y
2
=
3
cos
(
4
π
t
)
.
The resultant amplitude is :
Q.
A simple motion is represented by:
y
=
5
(
sin
3
π
t
+
√
3
cos
3
π
t
)
c
m
The amplitude and time period of the motion are:
Q.
A simple harmonic motion is represented by
y
=
5
(
sin
3
π
t
+
√
3
cos
3
π
t
)
c
m
The amplitude and time period of the motion are :
Q.
A simple harmonic motion is represented by:
y
=
5
(
sin
3
π
t
+
√
3
cos
3
π
t
)
cm
The amplitude and time period of the motion are:
Q.
Assertion :Two simple harmonic motions are given by
y
1
=
10
sin
(
3
π
t
+
π
4
)
and
y
2
=
5
sin
3
π
t
+
√
3
cos
3
π
t
These have amplitudes in the ratio
1
:
1.
Reason :
y
2
represents two simple harmonic motions each of amplitude
5
and so total amplitude is
10
, same as that of
y
1
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