Question

A simplified application MO theory to the hypothetical 'molecule' $OF$ would gives its bond order as:

• A. $2$
• B. $1.5$
• C. $1.0$
• D. $0.5$

Answer 1

The correct option is B $1.5$

$OF$

$O=$ Each oxygen atom has $2+6=$ 8 electrons
$F=$ Each fluorine atom has $2+7=9$ electrons
$O==\sigma 1s^2\sigma 1s^2\sigma 2s^2\sigma 2s\sigma 2p^{2}x\{\begin{array}{c}\pi 2p{y}^1\\ \pi 2p{z}^1\end{array}$
$F==\sigma 1s^2\sigma 1s^2\sigma 2s^2\sigma 2s^2\sigma 2p{x}^2\{\begin{array}{c}\pi 2p{y}^2\\ \pi 2p{z}^1\end{array}$

Bond order $=\frac{\text{No. of bonding - No. of anti-bonding}}{2}$

$=\frac{10-7}{2}$

$=\frac{3}{2}=1.5$