A simply supported beam $A C$ of span 8 m is supported at end A and at point B distance 5 m from end A having a uniformly distributed load of intensity 4.8 kN/m over the supported span and a concentrated load of 20 kN at the free end. The point of location of maximum bending moment and its magnitude is:

60 k N - m

^{'} B^{'}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

45 k N - m

2.6 m

from

^{'} A^{'}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

68 k N - m

3.08 m

from

^{'} A^{'}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

82 k N - m

^{'} B^{'}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $60 k N - m$ at $^{'} B^{'}$

Point of location of maximum bending moment will be the point where slope of BMD is zero i.e., shear force is zero.

$5 R_{A} - 4.8 \times 5 \times \frac{5}{2} + 20 \times 3 = 0$
$\Rightarrow R_{A} = 0 k N$
And $R_{B} = 4.8 \times 5 + 20 - 0$
$R_{B} = 44 k N$
$M_{m a x} = M_{B} = - 20 \times 3 = - 60 k N - m$

Suggest Corrections

Similar questions

Q. A simply supported beam of span length

6 m

and

75 m m

diameter carries a uniformly distributed load of

1.5 k N / m

.

What is the maximum value of bending moment?

Q. A simply supported beam of span length

6 m

and

75 m m

diameter carries a uniformly distributed load of

1.5 k N / m

.

What is the maximum value of bending stress?

Q. A simply supported beam 'A' carries a point load at its mid span. Another identical beam 'B' carries the same magnitude of load but it is uniformly distributed over the entire span. The ratio of the maximum deflections of beams 'A' and 'B' will be

Four wheel loads of 6 kN, 4 kN,8kN and 5 kN cross a girder of 20 m span followed by uniformly distributed load of 4 kN/m and 4 m long with the 6 kN load leading. The magnitude of bending moment at a section 8 m from the left support is kNm.

Q. A uniformly distributed load intensity, w, acting on a simply supported prestressed concrete beam of span, L, producing a bending moment, M, at mid-span is to be balanced by a parabolic tendon with zero eccentricity at ends and eccentricity e, at mid-span. The prestressing force required depends on:

Join BYJU'S Learning Program

The correct option is A 60kN−m at ′B′ Point of location of maximum bending moment will be the point where slope of BMD is zero i.e., shear force is zero. 5RA−4.8×5×52+20×3=0 ⇒ RA=0kN And RB=4.8×5+20−0 RB=44kN Mmax=MB=−20×3=−60kN−m