Question

# A simply supported beam AC of span 8 m is supported at end A and at point B distance 5 m from end A having a uniformly distributed load of intensity 4.8 kN/m over the supported span and a concentrated load of 20 kN at the free end. The point of location of maximum bending moment and its magnitude is:

A
60kNm at B
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B
45kNm at 2.6m from A
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C
68kNm at 3.08m from A
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D
82kNm at B
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Solution

## The correct option is A 60kN−m at ′B′ Point of location of maximum bending moment will be the point where slope of BMD is zero i.e., shear force is zero. 5RA−4.8×5×52+20×3=0 ⇒ RA=0kN And RB=4.8×5+20−0 RB=44kN Mmax=MB=−20×3=−60kN−m

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