Question

A simply supported beam is subjected to a uniformly distributed load of intensity w per unit length, on half of the span from one end. The length of the span and the flexural stiffness are denoted as l and EI respectively. The deflection at mid-span of the beam is

• A. $\frac{5}{6144}\frac{w{l}^4}{EI}$
• B. $\frac{5}{768}\frac{w{l}^4}{EI}$
• C. $\frac{5}{384}\frac{w{l}^4}{EI}$
• D. $\frac{5}{192}\frac{w{l}^4}{EI}$

Answer 1

The correct option is B $\frac{5}{768}\frac{w{l}^4}{EI}$


$\delta =\frac{5}{384}\frac{w{l}^4}{EI}$
$\Rightarrow {\delta }_1={\delta }_2$
$\delta ={\delta }_1+{\delta }_2=2{\delta }_1$
$\Rightarrow {\delta }_1=\frac{\delta }{2}=\frac{5}{768}\frac{w{l}^4}{EI}$