Question

A simply supported beam of length 4 m is subjected to a uniformly distributed load of 2 kN/m. What is the maximum shear stress if the cross-section is rectangular, 100 mm wide and 200 mm deep?

• A. $0.2N/m{m}^2$
• B. $0.1N/m{m}^2$
• C. $0.4N/m{m}^2$
• D. $0.3N/m{m}^2$

Answer 1

The correct option is D $0.3N/m{m}^2$

$\because V_{max}=\frac{wL}{2}=\frac{2\times 4}{2}=4kN$

$\because {\tau }_{avg}=\frac{V_{max}}{bd}=\frac{4\times {10}^3}{100\times 200}=0.2MPa$

$\because {\tau }_{max}=1.5{\tau }_{avg}=1.5\times 0.2=0.3MPa$