Question

A simply supported beam of span 5000 mm is loaded with a uniformly distributed load of 40 kN/m. Assuming yield strength of steel, $f_y$ = 250 MPa, required section modulus is _____$c{m}^3$ .
[Use wsm]

• A. 757.58

Answer 1

The correct option is A 757.58
Maximum bending moment

$M=\frac{w{l}^2}{8}=\frac{40\times 5^2}{8}=125kNm$

Required section modulus

$Z_{req}=\frac{M}{0.66f_y}=\frac{125\times {10}^6}{0.66\times 250}$

$=757575.75m{m}^3$

$=757.576c{m}^3$