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Question

(a) sin6π5+i(1+cos6π5)
(b) i1i(1cos2π5)+sin2π5

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Solution

2sin3π5cos3π5+i.2cos23π5
2cos3π5[sin3π5+icos3π5]
But r=2cos3π5=ive
Hence are rewrite as under:
z=2cos3π5[sin3π5icos3π5]
=2cos3π5[cos(3π23π5)+isin(3π23π5)]
=2cos3π5[cos9π10+isin9π10]
r=2cos3π5(+ive)
and θ=9π10 and which lives between π and π

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