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Question

a sin x = X
b cos x =Y
Then what is x2÷a2+y2÷b2

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Solution


a sin x = X
b cos x =Y
X2a2+Y2b2=a2sin2xa2+b2cos2xb2
=a2(sin2x1)+b2(cos2x1)
=a2cos2x+b2sin2x.

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