A single $6$ -sided die is rolled. What is the probability of rolling a $4$ on the die?

\frac{1}{12}

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\frac{2}{3}

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\frac{3}{2}

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\frac{1}{6}

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Solution

The correct option is C $\frac{1}{6}$
Sample space of die $= 1, 2, 3, 4, 5, 6$
So, the total number of trials $= 6$
$P$ (getting $4$ on the die) $=$ $\frac{N u m b e r o f t i m e s 4 a p p e a r e d}{T o t a l n u m b e r o f t r i a l s}$
$=$ $\frac{1}{6}$

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