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Standard XII

Physics

Law of Conservation of Mechanical Energy

A single cons...

Question

A single conservative force F(x) acts on a $1.0 k g$ particle that moves along the x-axis.The potential energy U(x) is given by $U (x) = 20 + (x - 2)^{2}$ where $x$ is in meters.At $x = 5.0 m$ , the particle has a kinetic energy of $20 J$ . What is the mechanical energy of the system?

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Solution

Mechanical energy $= K . E + P . E$
$20 J + U (x = 5 m)$
$= 20 + 20 + (5 - 2)^{2}$
$= 40 + 9 = 49 J$

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A single conservative force F(x) acts on a 1.0kg particle that moves along the x-axis.The potential energy U(x) is given by U(x)=20+(x−2)2 where x is in meters.At x=5.0m, the particle has a kinetic energy of 20J. What is the mechanical energy of the system?

Mechanical energy =K.E+P.E20J+U(x=5m)=20+20+(5−2)2=40+9=49J

A single conservative force F(x) acts on a $1.0 k g$ particle that moves along the x-axis.The potential energy U(x) is given by $U (x) = 20 + (x - 2)^{2}$ where $x$ is in meters.At $x = 5.0 m$ , the particle has a kinetic energy of $20 J$ . What is the mechanical energy of the system?

Mechanical energy $= K . E + P . E$
$20 J + U (x = 5 m)$
$= 20 + 20 + (5 - 2)^{2}$
$= 40 + 9 = 49 J$