Question

A single die is rolled. Find the probability of the sum of the five visible faces being greater than or equal to 19.

Answer 1

The sum of the six values on a die = 1 + 2 + 3 + 4 + 5 + 6 = 21
For the sum of the five visible faces to be greater than or equal to 19, the value facing down should be less than or equal to 2.

For this event, there are 6 outcomes of which 2 are favourable.
Hence, the required probability is $\frac{2}{6}$= $\frac{1}{3}$