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Inertia

A single hori...

Question

A single horizontal force F is applied to a block of mass $M_{1}$ which is in contact with another block of mass $M_{2}$ as shown in the figure. If the surfaces are friction less, the force between the block is:

\frac{M_{1} F}{M_{2}}

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\frac{M_{1} M_{2} F}{M_{1} + M_{2}}

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\frac{M_{2} F}{M_{1} + M_{2}}

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\frac{M_{2} F}{M_{1}}

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Solution

The correct option is C $\frac{M_{2} F}{M_{1} + M_{2}}$
We know that acceleration $a = \frac{F}{M}$
$\Rightarrow a = \frac{F}{M_{1} + M_{2}}$
So, the force between the two block, $F = M_{2} \times a$
$\Rightarrow F = M_{2} \frac{F}{M_{1} + M_{2}}$

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A single horizontal force F is applied to a block of mass M1 which is in contact with another block of mass M2 as shown in the figure. If the surfaces are friction less, the force between the block is:

The correct option is C M2FM1+M2We know that acceleration a=FM⇒a=FM1+M2So, the force between the two block, F=M2×a⇒F=M2FM1+M2

A single horizontal force F is applied to a block of mass $M_{1}$ which is in contact with another block of mass $M_{2}$ as shown in the figure. If the surfaces are friction less, the force between the block is:

The correct option is C $\frac{M_{2} F}{M_{1} + M_{2}}$
We know that acceleration $a = \frac{F}{M}$
$\Rightarrow a = \frac{F}{M_{1} + M_{2}}$
So, the force between the two block, $F = M_{2} \times a$
$\Rightarrow F = M_{2} \frac{F}{M_{1} + M_{2}}$