A single phase full bridge diode rectifier is supplied from 230 V- 50 Hz source- The load consists of R -10 - and a large inductance so as to render the load current constant- The input supply power factor is lagging-

Average value of output voltage, V_0 =2V_m/π =2 ×√(2)× 230 /π V_0 = 207 .07 V Average value of output current, I_0 =V_0/R =207.07/10 = 20.707 A Input source c ...

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1-Phase Diode Bridge Rectifiers RL Load

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A single phase full bridge diode rectifier is supplied from 230 V, 50 Hz source. The load consists of $R = 10 Ω$ and a large inductance so as to render the load current constant. The input supply power factor is _____________lagging.

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Solution

The correct option is A 0.9
Average value of output voltage,
$V_{0} = \frac{2 V_{m}}{π} = \frac{2 \times \sqrt{2} \times 230}{π}$
$V_{0} = 207 .07 V$

Average value of output current,
$I_{0} = \frac{V_{0}}{R} = \frac{207.07}{10} = 20.707 A$

$I n p u t s o u r c e c u r r e n t = I_{s} = I_{0} \sqrt{\frac{π}{π}} = I_{0} = 20.707 A$
$I n p u t s o u r c e r m s v o l t a g e = V_{s} = 230 V$
$I n p u t p o w e r f a c t o r = \frac{V_{0} I_{0}}{V_{s} I_{s}} = \frac{207.07 \times 20.707}{230 \times 20.707} = 0.90 l a g g i n g$

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A single phase full bridge diode rectifier is supplied from 230 V, 50 Hz source. The load consists of R=10 Ω and a large inductance so as to render the load current constant. The input supply power factor is _____________lagging. 0.9

A single phase full bridge diode rectifier is supplied from 230 V, 50 Hz source. The load consists of $R = 10 Ω$ and a large inductance so as to render the load current constant. The input supply power factor is _____________lagging.

0.9