Question

A single phase full bridge inverter is supplying an RL load from a source voltage of $200V$ dc. If the inverter is operating at $50Hz$, the load current at the end of first half cycle is _____ $A$

Answer 1

The output voltage and current waveforms are



$T=\frac{1}{f}=\frac{1}{50}=0.02s$

The circuit during first half cycle is



$I\left(t\right)=\frac{V_s}{R}(1-e^{-t/\tau })$
At the end of first half cycle,
$i\left(0.01\right)=\frac{200}{8}(1-e^{-t/\tau })$ [where as $\tau =\frac{L}{R}=0.0025s$]
$I\left(0.01\right)=\frac{200}{8}(1-e^{\frac{-0.01}{0.0025}})=24.54A$