A single-phase fully controlled the thyristor bridge ac-dc converter is operating at a firing angle of 25° and overlap angle of 10° constant dc output curent of 20 A. The fundamental power factor (displacement factor) at input ac mains is

Open in App

Solution

$F D F = cos (α + \frac{μ}{2})$

$= cos (25^{\circ} + \frac{10^{\circ}}{2}) = 0.866$

Suggest Corrections

Similar questions

Q. A 3-phase fully controlled bridge converter with free wheeling diode is fed from 400 V, 50 Hz AC source and is operating at a firing angle of 60°. The load current is assumed constant at 10 A due to high load inductance. The input displacement factor (IDF) and the input power factor (IPF) of the converter will be

A single phase fully controlled bridge rectifier is operated from 240 V, 50 Hz ac mains with firing angle $30^{0}$ . Load draws a continuous and ripple free current of 12 A. Then which of the following is correct ?

Q. The fully controlled thyristor converter in the figure is fed from a single-phase source. When the firing angle is 0°, the dc output voltage of the converter is 300 V. What will be the output voltage for a firing angle of 60°, assuming continuous conduction?

Q. A single phase fully controlled converter is connected to a

240 V

AC supply. If the converter is fired at an advance angle of

45^{o}

and overlap angle of

10^{o}

, then the mean load voltage is ____

V

Q. A three phase fully controlled bridge converter is feeding a load drawing a constant and ripple free load current of 10 A at a firing angle of 30°. The approximate Total Harmonic Distortion (%THD) and the rms value of fundamental component of the input circuit will respectively be

Join BYJU'S Learning Program

A single-phase fully controlled the thyristor bridge ac-dc converter is operating at a firing angle of 25° and overlap angle of 10° constant dc output curent of 20 A. The fundamental power factor (displacement factor) at input ac mains is

FDF=cos(α+μ2) =cos(25∘+10∘2)=0.866

$F D F = cos (α + \frac{μ}{2})$

$= cos (25^{\circ} + \frac{10^{\circ}}{2}) = 0.866$