Question

A single phase inverter is operating with PWM technique to eliminate $5^{th}$ harmonic content in the output. The rms value of $7^{th}$ harmonic content in the output is ___________$V_s$(Volts).

• A. 0.12

Answer 1

The correct option is A 0.12
To eliminate the $5th$ harmonic content,
$2d=\frac{2\pi }{5}$
$d=\frac{\pi }{5}={36}^o$
The $7th$ harmonic rms value is ,
$V_{07\left(rms\right)}=\frac{4V_s}{7\pi \sqrt{2}}sin\frac{7\pi }{2}sin(7\times {36}^o)=0.122V_s$