Question

A single-phase semi-converter connected to 230 V, 50 Hz source is feeding a load R = $10\Omega$ in series with a large inductance that makes the load current ripple free. The firing angle is ${30}^{\circ }$, then the current distortion factor is __________

• A. 0.95

Answer 1

The correct option is A 0.95
Current distortion factor for a single phase semi converter is

$=\frac{2\sqrt{2}cos\frac{\alpha }{2}}{\sqrt{\pi (\pi -\alpha )}}$

$=\frac{2\sqrt{2}cos\left(\frac{\pi }{12}\right)}{\sqrt{\pi (\pi -\frac{\pi }{6})}}=0.9526$