Question

A single phase semi converter, connected to 230 V, 50 Hz source is feeding a load$R=40\Omega$ in series with large inductor that makes the load current ripple free. If the value of firing angle is ${45}^o$, then the current distortion factor is

• A. 0.550
• B. 0.700
• C. 0.960
• D. 0.850

Answer 1

The correct option is C 0.960

Current distortion factor for single phase semi converter,

$CDF=\frac{2\sqrt{2}cos\left(\frac{\alpha }{2}\right)}{\sqrt{\pi (\pi -\alpha )}}$

$=\frac{2\sqrt{2}cos\left(\frac{45}{2}\right)}{\sqrt{\pi (\pi -\frac{\pi }{4})}}=\frac{2.613}{\sqrt{\frac{3{\pi }^2}{4}}}=\frac{2.613}{2.721}=0.960$