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Production

Surface Finish in Machining Part - II

A single poin...

Question

A single point turning tool is designated as follows:
$10^{\circ} - 12^{\circ} - 7^{\circ} - 5^{\circ} - 20^{\circ} - 50^{\circ} - 0.2 mm.$
If this tool is used for performing turning at feed rate of 0.1mm/rev, the maximum peak to valley height obtained in microns is

6.25

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25.4

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15.82

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None

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Solution

The correct option is B 25.4
Peak to valley, roughness (h)

$= \frac{f}{tan SCEA + cot ECEA}$

$= \frac{f}{tan 50 + cot 20}$

$= \frac{0.1}{tan 50 + cot 20}$

$= 0.02538 mm = 25.4 μ m$

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A single point turning tool is designated as follows: 10∘−12∘−7∘−5∘−20∘−50∘−0.2 mm. If this tool is used for performing turning at feed rate of 0.1mm/rev, the maximum peak to valley height obtained in microns is

The correct option is B 25.4Peak to valley, roughness (h) =ftanSCEA+cotECEA =ftan50+cot20 =0.1tan50+cot20 =0.02538 mm=25.4μm

A single point turning tool is designated as follows:
$10^{\circ} - 12^{\circ} - 7^{\circ} - 5^{\circ} - 20^{\circ} - 50^{\circ} - 0.2 mm.$
If this tool is used for performing turning at feed rate of 0.1mm/rev, the maximum peak to valley height obtained in microns is

The correct option is B 25.4
Peak to valley, roughness (h)

$= \frac{f}{tan SCEA + cot ECEA}$

$= \frac{f}{tan 50 + cot 20}$

$= \frac{0.1}{tan 50 + cot 20}$

$= 0.02538 mm = 25.4 μ m$