A single riveted lap joint of two similar plates as shown in the figure below has the following geometrical and material details.

width of the plate $w = 200 m m,$ thickness of the plate $t = 5 m m$ , number of rivets $n = 3$ , diameter of the rivet $d_{r} = 10 m m$ , diameter of the rivet hole $d_{n} = 11 m m$ , allowable tensile stress of the plate $σ_{p} = 200 M P a$ , allowable shear stress of the rivet $σ_{s} = 100 M P a$ and allowable bearing stress of the rivet $σ_{c} = 150 M P a$ .
If the plates are to be designed to avoid tearing failure,the maximum permissble load $P$ in $k N$ is

167

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501

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83

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125

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Solution

The correct option is A $167$
Tearing load
$= (W - 3 d) t \times σ_{P} = (200 - 3 \times 11) \times 5 \times 200$
$= 167 k N$

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The correct option is A 167Tearing load =(W−3d)t×σP=(200−3×11)×5×200 =167 kN

The correct option is A $167$
Tearing load
$= (W - 3 d) t \times σ_{P} = (200 - 3 \times 11) \times 5 \times 200$
$= 167 k N$