The correct option is C Diffraction fringes becomes narrower and crowded together
For red light λ=λr
∴βred=Daλr−−−−−(i)
For blue light, λ=λb
∴βblue=Daλb−−−−−−(ii)
∴βblueβred=DaλbDaλr=λbλr⇒βblue=λbλr×βred∴λb<λr∴βblue<βred
∴ Diffraction fringes become narrower and crowed together.