Question

A single solar cell of dimension $(10\text{cm}\times 10\text{cm})$ produces a voltage of $0.5\text{V}$ and current $2.5\text{A}$. The intensity of light absorbs by cell is $800{\text{W/m}}^2$. The efficiency of cell is -

• A. $15.6\%$
• B. $24\%$
• C. $12.3\%$
• D. $10.2\%$

Answer 1

The correct option is A $15.6\%$

We know that,

Efficiency, $\eta =\frac{P_{\text{out}}}{P_{\text{in}}}\times 100$

$\Rightarrow \eta =\frac{\left(V\right)\left(I\right)}{\left(\text{Intensity}\right)\times \text{Area}}\times 100$

$=\frac{0.5\times 2.5}{800\times 100\times {10}^{-4}}\times 100$

$\therefore \eta =\frac{125}{8}=15.6\%$

Hence, option $\left(\text{A}\right)$ is correct.