Question

A sinusoidal voltage of r.m.s. value of $200V$ is connected to the junction diode and a capacitor C in the circuit shown so that half wave rectification occurs. The final potential difference across C in volts is

• A. $213$
• B. $170$
• C. $283$
• D. $352$

Answer 1

Answer: (C)

$283$

Given,
$V_{rms}=200V$
We know the formula $V_{rms}=\frac{V_{applied}}{\sqrt{2}}$
So, $V_{applied}=200\sqrt{2}$
$\Rightarrow =282.8V$
$\Rightarrow =283V$.