CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A sinusoidal voltage V=200sin 314 t is appiled to a 10 Ω resistor. Find (i) rms voltage, (ii) rms current and (iii) power dissipated as heat.

Open in App
Solution

According to the question V=200sin314t and R=10Ω
comaring it with original equation we get ,Vm=200V
(1} rms voltage , Vrms=Vm2=0.707×200=141.4V
(2)rms current , Irms=VrmsR=141.410=14.14A

(3)power dissipate ,P=VrmsIrmscosθ
here cosθ is power factor which is equal to 1 for pure resistive circuit since voltage and current are in same phase,
p=141.4×14.14=1999.692000W


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Direct Current Vs Alternating Current
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon