A sinusoidal voltage $V (t) = 100 s i n (500 t)$ is applied across a pure inductance of $L = 0.02 H .$ The current through the coil is :

10 cos (500t)

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-10 cos (500t)

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10 sin (500t)

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-10 sin (500t)

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Solution

The correct option is B -10 cos (500t)
We know that voltage across inductor
$V = L \frac{d i}{d t}$
$i = \frac{1}{L} \int 100 s i n (500 t) d t$
$i = - 10 c o s 500 t$

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