Question

A siphon in action is shown in the figure. The liquid flowing through the siphon has a density of $1.5$g/cc. The difference of pressure at points $A$ and $D$ is $(g=980cm/s^2)$:-

• A. $2.65\times {10}^{4}N/m^2$
• B. $2.65\times {10}^{5}N/m^2$
• C. $2.65\times {10}^{3}N/m^2$
• D. Zero

Answer 1

Answer: (C)

$2.65\times {10}^{3}N/m^2$

Pressure differnce between two point in same liquid depend on height.

$P_2-P_1=\rho g(H_2-H_1)$

Here $P_A-P_D=\rho g(H_A-H_D)$

Putting values in SI units according to question

$P_A-P_D=1.5\times 1000\times 9.8\times \left(180\right)=2.65\times {10}^{3}N/m^2$

Hence option C is correct.