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Question

A siphon tube as shown in figure is discharging a liquid of density 900 kgm3. Atmospheric pressure is 1.01×105 Nm2.

A
The speed of liquid through siphon is 10 ms1
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B
Pressure at point C is 3.2×104 Nm2
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C
Pressure at point B is 4.25×104 Nm2
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D
Pressure at point C is 6.5×104 Nm2
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Solution

The correct options are
A The speed of liquid through siphon is 10 ms1
C Pressure at point B is 4.25×104 Nm2
D Pressure at point C is 6.5×104 Nm2
v = speed of liquid through siphon = 2gh
v=2×10×(4+1)=10 ms1
Apply Bernoulli's theorem at A and B , we have ,
P+0+0=PB+12ρv2+ρg(1.5)
PB=4.25×104Nm2
Apply Bernoulli's theorem, at B & C
PC=4.25×104+900×10×2.5=6.5×104 Nm2

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