A siphon tube is discharging a liquid of density 900 kg - m 3 as shown in figure- P 0-1-01 - 105 N - m 2The speed of liquid through the siphon isA- 6 m - sB- 8 m - sC- 10 m - sD- 12 m - s

The correct option is C 10 m/sv=√(2gh)=√(2×10×(4+1))=10 m/s ...

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Standard XII

Physics

SHM expression

A siphon tube...

Question

A siphon tube is discharging a liquid of density $900 \frac{k g}{m^{3}}$ as shown in figure.

$(P_{0} = 1.01 \times 105 N / m^{2})$

The speed of liquid through the siphon is

6 m/s

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8 m/s

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10 m/s

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12 m/s

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Solution

The correct option is C 10 m/s
$v = \sqrt{2 g h} = \sqrt{2 \times 10 \times (4 + 1)} = 10 m / s$

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A siphon tube is discharging a liquid of density 900kgm3 as shown in figure. (P0=1.01×105 N/m2) The speed of liquid through the siphon is

The correct option is C 10 m/sv=√2gh=√2×10×(4+1)=10 m/s

A siphon tube is discharging a liquid of density $900 \frac{k g}{m^{3}}$ as shown in figure.

$(P_{0} = 1.01 \times 105 N / m^{2})$

The speed of liquid through the siphon is

The correct option is C 10 m/s
$v = \sqrt{2 g h} = \sqrt{2 \times 10 \times (4 + 1)} = 10 m / s$