Question

A siphon tube is discharging a liquid of density $900\frac{kg}{m^3}$ as shown in figure.

$(P_0=1.01\times 105N/m^2)$


Pressure at point B is

• A. $4.25\times {10}^{4}N/m^2$
• B. $6.25\times 104N/m^2$
  
• C. $2.50\times {10}^{4}N/m^2$
  
• D. $2.0\times {10}^{5}N/m^2$

Answer 1

The correct option is A $4.25\times {10}^{4}N/m^2$

Applying Bernoulli's theorem at A and B, we have

$P_0+0+0=P_B+\frac{1}{2}\rho v^2+\rho g\left(1.5\right)$

or $P_B=(1.01\times {10}^5)–\frac{1}{2}\times 900\times (10{)}^2-900\times 10\times 1.5$

$=4.25\times {10}^{4}N/m^2$