A siren placed at a railway platform is emitting sound of frequency 5 kHz. A passenger sitting in a moving train A, records a frequency of 5.5 kHz while the train approaches the siren. During his return journey in a different train B, he records a frequency of 6.0 kHz while approaching the same siren. The ratio of the velocity of train B to that of train A is
2
In both the cases observer is moving towards, the source. Hence by using n′ = n(v+v0v)
When passenger is sitting in train A, then
5.5 = 5(v+vAv) ......(i)
When passenger is sitting in train B, then
6 = 5(v+vBv)
On solving equation (i) and (ii), we get vBvA = 2