A siren placed at a railway platform is emitting sound of frequency 5 kHz. A passenger sitting in a moving train A records a frequency of 5.5 kHz while the train approaches the siren. During his return journey in a different train B he records a frequency of 6.0 kHz while approaching the same siren. The ratio of the velocity of train B to that of train A is
In both the cases observer is moving towards the source.Hence by using n′=n(v+v0v)
When passenger is sitting in train A, then
5.5=5(v+vAv) ....(i)
When passenger is sitting in train B, then
6=5(v+vBv) ....(ii)
On solving equation (i) and (ii) we get vBvA=2