Question

A six face dice is marked with the numbers 1, 2, 3, 4, 5 and 6. What is the probability of getting a number which is not even?

• A. $\frac{1}{3}$
• B. $\frac{2}{3}$
• C. $\frac{3}{4}$
• D. $\frac{1}{2}$

Answer 1

The correct option is D $\frac{1}{2}$

Even numbers on the dice are : 2, 4 and 6.
$\therefore$Favorable outcomes(total no. of even numbers) = 3
$\text{Probability P(E)}$ = $\frac{\text{Number of outcomes favorable to E}}{\text{Number of all possible outcomes of the experiment}}$

Let $E$ be the event of getting an even number $=\frac{3}{6}=\frac{1}{2}$
Event F, (Probability of not getting an even number) is the complement event of E.(Sum of probabilites of two complements events is always $1$.)

$\therefore$ P(F) or P(complement event of E) $=1-\frac{1}{2}=\frac{1}{2}$