wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A skater of mass m standing on ice throws a stone of mass M with a velocity of v m/s in a horizontal direction. Find the distance over which the skater will move back if the coefficient of friction between the skaters and the ice is m.


A

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A


Coservation of momentum yields,

MV = mu u = MVm where 'u' is the recoil velocity of the skater.

Since the skater stops after covering a distance 'S'

02 - u2 = 2as

02 - u2 - 2 (- μg) s [a = - μg]

s = u22μg


flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Circular Permutations
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon