A skater of mass m standing on ice throws a stone of mass M with a velocity of v m/s in a horizontal direction. Find the distance over which the skater will move back if the coefficient of friction between the skaters and the ice is m.
Coservation of momentum yields,
MV = mu ⇒ u = MVm where 'u' is the recoil velocity of the skater.
Since the skater stops after covering a distance 'S'
⇒ 02 - u2 = 2as
⇒ 02 - u2 - 2 (- μg) s [a = - μg]
⇒ s = u22μg