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Question

A slender homogeneous rod of length 2L floats partly immeresed in water, being supported by a string fastened to one od its end, as shown. The length of rod that extends out of water is-
1190711_d3dbf33d99b94e199c29b5f18d5812fb.png

A
L
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B
L/2
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C
L/4
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D
3L
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Solution

The correct option is B L/2
Let h be height of root inside water
A= area of cross section
d= density of root
dw= density of water
mass of rod = mass of mass displaced
d×A×2l=dw×h×A
h=2l×d/dw=21×0.75=3L/2
Height of rod outside water =12.

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