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Question

A slider crank mechanism has slider mass of 10 kg, stroke of 0.2 m and rotates with a uniform angular velocity of 10 rad/s. The primary inertia forces of the slider are partially balanced by a revolving mass of 6 kg at the crank, placed at a distance equal to crank radius. Neglect the mass of connecting rod and crank. When the crank angle (with respect to slider axis) is 30o, the unbalanced force(in newtow) normal to the slider axis is

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Solution

Given:
mp=10kg,m=6kg,r=0.1m,ω=10rad/s,θ=30o


r=s2=0.1m
Unbalanced force =mω2r sin30o
=6×100××0.1×12=30 N

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