Question

A sludge obtained from digestion tank has a solid content of 12%. The total solids in the sludge are 2kg. The average density of solids in the sludge is 1.65. The density of sludge ($kg/m^3$, rounded off to two decimal place) is

• A. 1049

Answer 1

The correct option is A 1049
Given, Total solids=2kg

$massofwater=\frac{88}{12}\times 2=14.667kg$
$Volumeofsludge=volumeofwater+Volumeofsolids$
$=\frac{14.667}{1000}+\frac{2}{1650}$
$=0.01588m^3$
$Densityofsludge=\frac{Massofwater+Massofsolids}{Volumeofsludge}$
$\frac{2+14.667}{0.01588}$
$=1049.64kg/m^3$