A small air bubble is trapped inside a transparent cube of side 12 cm. When viewed from 1st face it appears at 5 cm and when viewed at opposite face it appears at 3 cm. Actual distance of bubble from 1st face in cm is (Write upto two digits after the decimal point)

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Solution

$5 = \frac{d}{μ} \dots (1)$
$3 = \frac{12 - d}{μ} \dots (2)$

By (1) and (2), d = 7.5 cm

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A small air bubble is trapped inside a transparent cube of side 12 cm. When viewed from 1st face it appears at 5 cm and when viewed at opposite face it appears at 3 cm. Actual distance of bubble from 1st face in cm is (Write upto two digits after the decimal point)

5=dμ…(1) 3=12−dμ…(2) By (1) and (2), d = 7.5 cm

$5 = \frac{d}{μ} \dots (1)$
$3 = \frac{12 - d}{μ} \dots (2)$

By (1) and (2), d = 7.5 cm