Question

A small bar magnet of moment M is placed in a uniform field H. If magnet makes an angle of ${30}^{\circ }$ with field, the torque acting on the magnet is

• A. MH
• B. $\frac{MH}{2}$
  
• C. $\frac{MH}{3}$
  
• D. $\frac{MH}{4}$

Answer 1

The correct option is B $\frac{MH}{2}$


$\tau =MHsin\theta =MHsin{30}^{\circ }=\frac{MH}{2}$