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Question

A small block B of mass 1 kg is placed on block A of mass 5 kg and length 20 cm as shown in figure. A constant horizontal force of 10 N is applied on block A. If all the surfaces are assumed frictionless and block B is at the right end of block A, then the time in which block B separates from A is
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A
0.2s
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B
0.5s
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C
2s
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D
3s
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Solution

The correct option is A 0.2s
10N acts on the 5kg block.
The acceleration of the 5kg block is hence a=Fm=2ms2
Distance the 5kg block has to traverse before the smaller block falls is 20cm (0.2m).
using the equation of motion.
s=ut+12at2
0.2=12(2)(t2)
t=0.2s

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