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Question

A small block of mass m is placed on a body of mass M at rest. If the block is set in horizontal motion with velocity v as shown,

(Assume that the small block leaves from surface of M vertically at A and all surfaces are smooth)
Find velocity of mass M, when the small block leaves the surface of M.

A
MvM+m
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B
mvM
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C
mvM+m
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D
Mvm
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Solution

The correct option is C mvM+m
When the small block leaves the surface of M, its velocity towards right (along x axis) equals the velocity of the body M.
Let it be vx
There is no net external force in horizontal direction, so linear momentum will be conserved for the system
mv=(M+m)vx
vx=mvM+m

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