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Surface Tension

A small block...

Question

A small block of wood, of density $0.4 \times 10^{3} k g / m^{3}$ , is submerged in water at a depth of $2.9 m$ . Find the acceleration of the block toward the surface when the block is released.

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Solution

$A c c e l e r a t i o n, a = \frac{u p t h r u s t - w e i g h t}{m a s s}$

$= \frac{(V) (1000) (9.8) - (V) (0.4 \times 10^{- 3}) (9.8)}{(V) (0.4 \times 10^{3})}$

$= 14.7 m / s^{2}$

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