A small block of wood of relative density 0.5 is submerged in water at a depth of 5m. When the block is released, it starts moving upwards, the acceleration of the block is: (g=10ms−2)
A
5ms−2
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B
10ms−2
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C
7.5ms−2
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D
15ms−2
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Solution
The correct option is B10ms−2 Total upward force=(upward−downwardforce)=ma v×g×1000−500gy=500v×a 500g=500a a=g So, a=10m/s2