Question

A small block oscillates back and forth on a smooth concave surface of radius R. The time period of small oscillation is

• A.
• B.
• C.
• D. $2\pi \sqrt{\frac{R}{3g}}$

Answer 1

The correct option is A

$a=-gsin\theta$

$=-g\theta =-g\frac{x}{R}$

$a=-\left(\frac{g}{R}\right)x\Rightarrow w^2=\left(\frac{g}{R}\right)\Rightarrow T=2\pi \sqrt{\frac{R}{g}}$