A small body (Biot number < 0.1) has temperature variation as T=A+BeCτ,τ= time in seconds
Where A, B, and C are constants.
If that small body is used as thermocouple its time constant is given by
A
-1/C
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B
1/C
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C
-C
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D
C
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Solution
The correct option is A -1/C In luped analysis temperature variation is given by T−T∞Ti−T∞=ehAρvcτ ...(i)
Given equation, T=A+BeCτ T−AB=eCτ ...(ii)
Compare (i) and (ii) A=T∞,B=Ti−T∞ C+−hAρvc
Now time constant is given by τ0=ρvchA τ0=−1C