A small body is projected up a rough - - 12 inclined plane - - 60- with a speed of v - 10 m-s as shown- How far along the plane it moves up before coming to rest- Take g - 10 m-s2

We know that work done by all forces = change in K.E.— 1And work done = net force x displacement #160;ThereforeW.D. = (umgcos@ +mgsin@)x displacement (umg ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Physics

Work

A small body ...

Question

A small body is projected up a rough $(μ = \frac{1}{2})$ inclined plane $(θ = 60^{\circ})$ with a speed of $v = 10 m / s$ as shown. How far along the plane it moves up before coming to rest? (Take $g = 10 m / s^{2}$ )

Open in App

Solution

We know that work done by all forces = change in K.E.----1

And work done = net force x displacement

Therefore

W.D. = (umgcos@ +mgsin@)x displacement

$(u m g cos θ + m g sin θ) \times d i s p l a c e m e n t (s) = \frac{1}{2} m v v$

$(\frac{1}{2} \times 10 \times \frac{1}{2} + 10 \times \frac{\sqrt{3}}{2}) \times s = \frac{1}{2} m (100)$

$s = \frac{20}{2 \sqrt{3} + 1}$

Suggest Corrections

Similar questions

Q. A block slides down an inclined plane of slope

θ

with constant velocity. It is then projected up the plane with an initial speed

v_{0}

. How far up the incline will it move before coming to rest?

Q. A block slides down on an inclined plane of slope angle

θ

with constant velocity. It is then projected up on the same plane with initial velocity

V_{0}

. How far up the incline will it move before coming to rest

Q. A block slides down a rough inclined plane of slope angle

θ

with a constant velocity. It is then projected up the same plane with an initial velocity v. The distance travelled by the block up the plane before coming to rest is

Q. A body slides down a rough inclined plane of inclination

θ

with constant velocity

v

. If it is projected up the plane with velocity

2 v

, then it moves up the plane with

Q. A block slides down a slope of angle

θ

with constant velocity. It is then projected up with a velocity of

10 {m s}^{- 1}

g = 10 {m s}^{- 2}

and

q = 30^{o}

. The maximum distance it can go up the plane before coming to stop is

Join BYJU'S Learning Program

A small body is projected up a rough (μ=12) inclined plane (θ=60∘) with a speed of v=10m/s as shown. How far along the plane it moves up before coming to rest? (Take g=10m/s2)

We know that work done by all forces = change in K.E.----1And work done = net force x displacement ThereforeW.D. = (umgcos@ +mgsin@)x displacement(umgcosθ+mgsinθ)×displacement(s)=12mvv(12×10×12+10×√32)×s=12m(100)s=202√3+1

A small body is projected up a rough $(μ = \frac{1}{2})$ inclined plane $(θ = 60^{\circ})$ with a speed of $v = 10 m / s$ as shown. How far along the plane it moves up before coming to rest? (Take $g = 10 m / s^{2}$ )