A small body of superdense material, whose mass is twice the mass of the Earth but whose size is very small compared to the size of the Earth, starts from rest at a height H R above the Earth’s surface, and reaches the Earth’s surface in time t. Then t is equal to

$\sqrt{\frac{2 H}{g}}$

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$\sqrt{\frac{H}{g}}$

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$\sqrt{\frac{2 H}{3 g}}$

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$\sqrt{\frac{4 H}{3 g}}$

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Solution

The correct option is C
$\sqrt{\frac{2 H}{3 g}}$

In this case, body moves towards the earth with acceleration g and earth moves towards the body with acceleration 2g. Hence, relative acceleration is 3g and $T = \sqrt{\frac{2 H}{3 g}}$

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A small body of superdense material, whose mass is twice the mass of the Earth but whose size is very small compared to the size of the Earth, starts from rest at a height H R above the Earth’s surface, and reaches the Earth’s surface in time t. Then t is equal to

The correct option is C √2H3g In this case, body moves towards the earth with acceleration g and earth moves towards the body with acceleration 2g. Hence, relative acceleration is 3g and T=√2H3g

The correct option is C
$\sqrt{\frac{2 H}{3 g}}$

In this case, body moves towards the earth with acceleration g and earth moves towards the body with acceleration 2g. Hence, relative acceleration is 3g and $T = \sqrt{\frac{2 H}{3 g}}$