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Question

A small bucket of mass M is attached to a long inextensible cord of length L. the bucket is released from rest when the cord is in a horizontal position. In its lowest position the bucket scoops up m of water, what is the height of the swing above the lowest position?

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Solution

Atthelowestpositionthevelocityofthebucketis2gLKEofthebucketisMgL.Thenitscoopssomewaterso,itsweightbecomesM+m.VelocityofthebucketjustafteritscoopssomewaterisM2gL=(M+m)vv=M2gLM+mmaximumheightreachedisv22g=(MM+m)2L

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