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Question

A small catchment of area 150 ha received a rainfall of 10.5 cm in 90 minutes,due to a storm. At the outlet of the catchment, the stream draining the catchment was dry before the storm and experiences a runoff for 10 hours with an average discharge value of 2.5 m3/sec.The stream was again dry after the runoff event. The amount of water which was not available to runoff due to combined effect of infiltration, evaporation and transpiration is ____ m3

A
96×104
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B
67500
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C
247500
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D
114×104
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Solution

The correct option is B 67500
PR=Q

P=Input due to precipitation in 10 hours
=150×100×100×10.5100m3=157500 m3

R=Runoff=2.5×10×60×60=90000 m3

Q=15750090000=67500 m3

Hence, the volume of water not available to runoff
=67500 m3

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